One, understand

Yellow, white

Blue - green corner block center block

Red, orange

1. Standard, the color of six faces is "similar in color and back to back";

2. No matter how it is rotated, the center of each side will not be rotated. Therefore, when rotating, the center should be taken as the object.

3. The remaining pieces are called "corner blocks" (8 pieces) in 3 colors and "edge blocks" (12 pieces) in 2 colors.

4. The commonly used rubik's cube reduction method is according to the layer method: that is, first restore the first layer, then the second layer, and finally the third layer;

5. Basic terms

The rubik's cube can only be restored after rotation. From the direction facing it, it can be rotated clockwise (+) and counterclockwise (-).

Sometimes you have to rotate 180 degrees (" 2 "); We're going to write it as follows;

Expression: front + (front clockwise 90 degrees), right - (right counterclockwise 90 degrees), top 2 (top clockwise 180 degrees).

The third layer

The six faces, which face themselves, are called "anterior", and the others in turn are shown below.

Before =F(Front) =B(Back) left =L() Right =R(Right)

Expression: F(front clockwise 90 degrees), R' (right counterclockwise 90 degrees), U2 (top clockwise 180 degrees).

Solve the rubik's cube

1. Restore the first layer

At the first level, it can be realized as long as you explore for a while (it is necessary). The general order principle is:

PI center; Bamboo restores the first edge; Resided opposite (and other) edges; Student: to restore the angles.

Note: the first layer is not only aligned with the color of the side, but also with the correct position of the edges and corners (as shown in the right).

After one layer reduction

2. Restore the second layer

After putting the first layer together, turn the rubik's cube upside down and let the finished layer become the "bottom".

After careful observation, the restoration of the second layer is only required to complete the reduction of 4 middle-level edges.

And four middle edges, after all, have only two states: 1 to 2, or 1 to 3.

Step1: reverse 1 and 2

English: (top -, left -),(top +, left +)

English :(U 'l '), (UFU 'f ')

Condition 2: swap 1 and 3 for the two states of the second layer

English: (top +, right +),(top -, right -)

English :(U'R'), (U'F'UF)

3. Restore the third layer

Horizontal. Edge transposition: as shown in the picture on the right, the third floor has 4 edges.

Creeping: swap 1 and 2

English: (top +, front +, right +, top +), (right -, top -, front -)

English :(UF), (R'U'F')

1 please - > 2 swaps

The colors should be correct as well as the position. Simplified and universal conversion is adopted here:

Firstly, the edge block that needs to be turned over is placed in the position of "1" in the right figure, and the flip is carried out as follows:

After that, continue rotating the remaining unrestored edges of the upper layer clockwise to the position of "1", repeating the following method.

Note: at this point, when the upper four edges are not fully restored, the lower two layers will also be disorderly.

Don't worry, after the upper edge is all OK, the lower two layers are also restored naturally.

Situation: turn 1 (and other edges) in situ

English: [right +, horizontal middle layer - (from top to bottom)] x 4 turns 1(and other edges) in place

English :(R, horizontal middle layer ') * 4

Torque: the formula for angular displacement is the longest and needs to be remembered. As shown in the picture on the right, swap the order of 1, 2 and 3.

Condition 1: the order of 1 to 2 to 3 to 1 is interchanged.

English: {left -, [(right +, up +), (right -, up -)], left +, (up +, right +), (up -, right -)]

English: L 'R' U ', LURU 'R'

Condition 2: the order of 1 to 3 to 2 to 1 is interchanged. I'm going to replace the 1, 2, and 3 angles

English: {left -, [(right +, up -), (left +, up +)], right -, (up -, left -), (up +, left +)]

English: L 'RU LU, R' U 'L'

The color is correct in the position and the color in the position. Simplified and universal conversion is adopted here:

First, the corner block that needs to be turned over is placed in the position of "1" in the right figure, and the following method is used to reverse it.

After OK, continue to rotate the other unrestored edges of the upper layer clockwise to the position of "1", repeating the following method.

Note: here, when the upper four corners are not fully restored, the lower two layers will be in chaos.

Don't worry, after the upper corner is all OK, the lower two layers are also restored naturally.

Situation: turn 1 (and other corners) in situ

English: (right +, front -), (right -, front +)

English: 'R'F 'x N